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adjoint representation : ウィキペディア英語版
adjoint representation

In mathematics, the adjoint representation (or adjoint action) of a Lie group ''G'' is a way of representing the elements of the group as linear transformations of the group's Lie algebra, considered as a vector space. For example, in the case where ''G'' is the Lie group of invertible matrices of size ''n'', ''GL(n)'', the Lie algebra is the vector space of all (not necessarily invertible) ''n''-by-''n'' matrices. So in this case the adjoint representation is the vector space of ''n''-by-''n'' matrices x , and any element ''g'' in ''GL(n)'' acts as a linear transformation of this vector space given by conjugation: x \mapsto g x g^ .
For any Lie group, this natural representation is obtained by linearizing (i.e. taking the differential of) the action of ''G'' on itself by conjugation. The adjoint representation can be defined for linear algebraic groups over arbitrary fields.
==Definition==

Let ''G'' be a Lie group and let \mathfrak g be its Lie algebra (which we identify with ''TeG'', the tangent space to the identity element in ''G''). Define the map
:\Psi : G \to \mathrm(G), \, g \mapsto \Psi_g
where Aut(''G'') is the automorphism group of ''G'' and the automorphism Ψ''g'' is defined by
:\Psi_g(h) = ghg^\,
for all ''h'' in ''G''. The differential of Ψ''g'' at the identity is an automorphism of the Lie algebra \mathfrak g. We denote this map by Ad''g'':
:d(\Psi_g)_e=\mathrm_g\colon \mathfrak g \to \mathfrak g.
To say that Ad''g'' is a Lie algebra automorphism is to say that Ad''g'' is a linear transformation of \mathfrak g that preserves the Lie bracket. The map
:\mathrm\colon G \to \mathrm(\mathfrak g), \, g \mapsto \mathrm_g
is called the adjoint representation of ''G''. This is indeed a representation of ''G'' since \mathrm(\mathfrak g) is a closed〔The condition that a linear map is a Lie algebra homomorphism is a closed condition.〕 Lie subgroup of \mathrm(\mathfrak g) and the above adjoint map is a Lie group homomorphism. Note Ad is a trivial map if ''G'' is abelian.
If ''G'' is an (immersed) Lie subgroup of the general linear group GL_n(\mathbb), then, since the exponential map is the matrix exponential: \operatorname(X) = e^X, taking the derivative of \Psi_g(\operatorname(tX)) = ge^g^ at ''t'' = 0, one gets: for ''g'' in ''G'' and ''X'' in \mathfrak,
:\operatorname_g(X) = gX g^
where on the right we have the products of matrices.

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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